第05章_条件构造器和常用接口

1.Wrapper介绍

Wrapper ：条件构造抽象类，最顶端父类
- AbstractWrapper ：用于查询条件封装，生成 sql 的 where 条件
  - QueryWrapper ：查询条件封装
  - UpdateWrapper ： Update 条件封装
  - AbstractLambdaWrapper ：使用Lambda 语法
    - LambdaQueryWrapper ：用于Lambda语法使用的查询Wrapper
    - LambdaUpdateWrapper ： Lambda 更新封装Wrapper

2.QueryWrapper

组装查询条件

**执行SQL：**SELECT uid AS id,username AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 AND (username LIKE ? AND age BETWEEN ? AND ? AND email IS NOT NULL)

public void test01(){
    //查询用户名包含a，年龄在20到30之间，邮箱信息不为null的用户信息
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.like("username","a").between("age",20,30).isNotNull("email");
    List<User> users = userMapper.selectList(queryWrapper);
    users.forEach(System.out::println);
}

组装排序条件

**执行SQL：**SELECT uid AS id,username AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 ORDER BY age DESC,id ASC

public void test02(){
    //查询用户信息，按照年龄的降序排序，若年龄相同，则按照id升序排序
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.orderByDesc("age").orderByAsc("id");
    List<User> users = userMapper.selectList(queryWrapper);
    users.forEach(System.out::println);
}

组装删除条件

**执行SQL：**UPDATE t_user SET is_deleted=1 WHERE is_deleted=0 AND (email IS NULL)

public void test03(){
    //删除邮箱地址为null的用户信息
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.isNull("email");
    int result = userMapper.delete(queryWrapper);
    System.out.println(result > 0 ? "删除成功！" : "删除失败！");
    System.out.println("受影响的行数为：" + result);
}

条件的优先级

**执行SQL：**UPDATE t_user SET user_name=?, email=? WHERE is_deleted=0 AND (age > ? AND user_name LIKE ? OR email IS NULL)

public void test04(){
    //将（年龄大于20并且用户名中包含有a）或邮箱为null的用户信息修改
    UpdateWrapper<User> updateWrapper = new UpdateWrapper<>();
    updateWrapper.gt("age",20).like("username","a").or().isNull("email");
    User user = new User();
    user.setName("Oz");
    user.setEmail("test@oz6.com");

    int result = userMapper.update(user, updateWrapper);
    System.out.println(result > 0 ? "修改成功！" : "修改失败！");
    System.out.println("受影响的行数为：" + result);
}

**执行SQL：**UPDATE t_user SET username=?, email=? WHERE is_deleted=0 AND (username LIKE ? AND (age > ? OR email IS NULL))

public void test05(){
    //将用户名中包含有a并且（年龄大于20或邮箱为null）的用户信息修改
    UpdateWrapper<User> updateWrapper = new UpdateWrapper<>();
    updateWrapper.like("username","a").and(i->i.gt("age",20).or().isNull("email"));
    User user = new User();
    user.setName("Vz7797");
    user.setEmail("test@ss8o.com");

    int result = userMapper.update(user, updateWrapper);
    System.out.println(result > 0 ? "修改成功！" : "修改失败！");
    System.out.println("受影响的行数为：" + result);
}

组装select子句

**执行SQL：**SELECT username,age,email FROM t_user WHERE is_deleted=0

public void test06(){
    //查询用户的用户名、年龄、邮箱信息
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.select("username","age","email");
    List<Map<String, Object>> maps = userMapper.selectMaps(queryWrapper);
    maps.forEach(System.out::println);
}

实现子查询

**执行SQL：**SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 AND (uid IN (select uid from t_user where uid <= 100))

public void test07(){
    //查询id小于等于100的用户信息
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.inSql("uid", "select uid from t_user where uid <= 100");
    List<User> list = userMapper.selectList(queryWrapper);
    list.forEach(System.out::println);
}

3.UpdateWrapper

UpdateWrapper不仅拥有QueryWrapper的组装条件功能，还提供了set方法进行修改对应条件的数据库信息

public void test08(){
    //将用户名中包含有a并且（年龄大于20或邮箱为null）的用户信息修改
    UpdateWrapper<User> updateWrapper = new UpdateWrapper<>();
    updateWrapper.like("username","a").and( i -> i.gt("age",20).or().isNull("email")).set("email","svip@qq.com");
    int result = userMapper.update(null, updateWrapper);
    System.out.println(result > 0 ? "修改成功！" : "修改失败！");
    System.out.println("受影响的行数为：" + result);
}

4.condition

在真正开发的过程中，组装条件是常见的功能，而这些条件数据来源于用户输入，是可选的，因此我们在组装这些条件时，必须先判断用户是否选择了这些条件，若选择则需要组装该条件，若没有选择则一定不能组装，以免影响SQL执行的结果

思路一

**执行SQL：**SELECT uid AS id,user_name AS name,age,email,is_deleted FROM t_user WHERE is_deleted=0 AND (user_name LIKE ? AND age <= ?)

 public void test09(){
     String username = "a";
     Integer ageBegin = null;
     Integer ageEnd = 30;
     QueryWrapper<User> queryWrapper = new QueryWrapper<>();
     if(StringUtils.isNotBlank(username)){
         //isNotBlank判断某个字符创是否不为空字符串、不为null、不为空白符
         queryWrapper.like("user_name", username);
     }
     if(ageBegin != null){
         queryWrapper.ge("age", ageBegin);
     }
     if(ageEnd != null){
         queryWrapper.le("age", ageEnd);
     }
     List<User> list = userMapper.selectList(queryWrapper);
     list.forEach(System.out::println);
 }

思路二

上面的实现方案没有问题，但是代码比较复杂，我们可以使用带condition参数的重载方法构建查询条件，简化代码的编写

public void test10(){
    String username = "a";
    Integer ageBegin = null;
    Integer ageEnd = 30;
    QueryWrapper<User> queryWrapper = new QueryWrapper<>();
    queryWrapper.like(StringUtils.isNotBlank(username), "user_name", username)
        .ge(ageBegin != null, "age", ageBegin)
        .le(ageEnd != null, "age", ageEnd);
    List<User> list = userMapper.selectList(queryWrapper);
    list.forEach(System.out::println);
}

5.LambdaQueryWrapper

功能等同于QueryWrapper，提供了Lambda表达式的语法可以避免填错列名。

public void test11(){
    String username = "a";
    Integer ageBegin = null;
    Integer ageEnd = 30;
    LambdaQueryWrapper<User> queryWrapper = new LambdaQueryWrapper<>();
    queryWrapper.like(StringUtils.isNotBlank(username), User::getName, username)
        .ge(ageBegin != null, User::getAge, ageBegin)
        .le(ageEnd != null, User::getAge, ageEnd);
    List<User> list = userMapper.selectList(queryWrapper);
    list.forEach(System.out::println);
}

6.LambdaUpdateWrapper

功能等同于UpdateWrapper，提供了Lambda表达式的语法可以避免填错列名。

public void test12(){
    //将用户名中包含有a并且（年龄大于20或邮箱为null）的用户信息修改
    LambdaUpdateWrapper<User> updateWrapper = new LambdaUpdateWrapper<>();
    updateWrapper.like(User::getName, "a")
        .and(i -> i.gt(User::getAge, 20).or().isNull(User::getEmail));
    updateWrapper.set(User::getName, "小黑").set(User::getEmail,"abc@atguigu.com");
    int result = userMapper.update(null, updateWrapper);
    System.out.println("result："+result);
}

# 第05章_条件构造器和常用接口

#

# 1.Wrapper介绍

# 2.QueryWrapper

# 3.UpdateWrapper

# 4.condition

# 5.LambdaQueryWrapper

# 6.LambdaUpdateWrapper

第05章_条件构造器和常用接口

1.Wrapper介绍

2.QueryWrapper

3.UpdateWrapper

4.condition

5.LambdaQueryWrapper

6.LambdaUpdateWrapper